# Easy Question

find x:

$$1+8x^{-1}+15x^{-2}$$

I've got so far:

$$\frac{x^2+8x+15}{x^2}$$

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## Answers and Replies

find x for
$$1+8x^{-1}+15x^{-2}$$

and so far you got
$$\frac{x^2+8x+15}{x^2}$$

x can be anything, all real number, or even complex number.... apple, orange, banana.... just put what ever you want

sorry :) LOL ....ya a banana.....ok just simplify

If they're asking for all real numbers of x, then x can be anything but zero. Otherwise, like vincentchan said, x can be anything, even complex.

sorry :) LOL ....ya a banana.....ok just simplify.

(x+3)(x+5)=x^2+8x+15

vincent I know that but there is a x^2 underneath!

The answer in the book is

$$(1+\frac{5}{x})(1+\frac{3}{x})$$

can you simplify from my solution to your text book's one?
(x+3)(x+5)/x^2=(1+3/x)(1+5/x)

;) got it thanks mr.