- #1

- 243

- 0

find x:

[tex]1+8x^{-1}+15x^{-2}[/tex]

I've got so far:

[tex]\frac{x^2+8x+15}{x^2}[/tex]

[tex]1+8x^{-1}+15x^{-2}[/tex]

I've got so far:

[tex]\frac{x^2+8x+15}{x^2}[/tex]

Last edited:

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- Thread starter thomasrules
- Start date

- #1

- 243

- 0

find x:

[tex]1+8x^{-1}+15x^{-2}[/tex]

I've got so far:

[tex]\frac{x^2+8x+15}{x^2}[/tex]

[tex]1+8x^{-1}+15x^{-2}[/tex]

I've got so far:

[tex]\frac{x^2+8x+15}{x^2}[/tex]

Last edited:

- #2

- 609

- 0

[tex]1+8x^{-1}+15x^{-2}[/tex]

and so far you got

[tex]\frac{x^2+8x+15}{x^2}[/tex]

x can be anything, all real number, or even complex number.... apple, orange, banana.... just put what ever you want

- #3

- 243

- 0

sorry :) LOL ....ya a banana.....ok just simplify

- #4

- 793

- 4

- #5

- 243

- 0

sorry :) LOL ....ya a banana.....ok just simplify.

- #6

- 609

- 0

(x+3)(x+5)=x^2+8x+15

- #7

- 243

- 0

The answer in the book is

[tex](1+\frac{5}{x})(1+\frac{3}{x})[/tex]

- #8

- 609

- 0

can you simplify from my solution to your text book's one?

(x+3)(x+5)/x^2=(1+3/x)(1+5/x)

(x+3)(x+5)/x^2=(1+3/x)(1+5/x)

- #9

- 243

- 0

;) got it thanks mr.

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