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Easy resonance problem

  1. Feb 9, 2006 #1
    Please help me with this, it's one of the 'basic' problems and I can't do it at all. "The chains suspending a child's swing are 2.00 m long. At what frequency should a big brother push to make the child swing with largest amplitude?"

    Okay, so... the largest amplitude comes with a natural frequency...
    f1 = (1/2L)*(T/mu)^(1/2)

    I'm trying to figgure out why the rooted part gets to (g/L)^1/2... if T is mg and mu is m/L, wouldn't it be (gL)^1/2? And how does 1/2L turn into 1/2pi? Thanks for any help you can offer.
     
  2. jcsd
  3. Feb 9, 2006 #2

    Päällikkö

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    You are using a formula for transverse waves.

    With the small angle approximation, the period of a pendulum:
    [tex]T = 2\pi \sqrt{\frac{l}{g}}[/tex]
     
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