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Imagine a roulette with 38 pockets (0,00,1,2,3,....36)

Suppose you were to place bets on numbers 1,2,3,4.

What is the probability that at least one of your numbers would be the winner in two consecutive spins of the roulette wheel.

I am pretty sure the answer is either 4/38 X 4/38 , or 4/38 X 1/38.