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Easy Trigonometry Proof

  1. Aug 25, 2011 #1
    1. The problem statement, all variables and given/known data
    Prove or disprove the following equation.

    (n+[itex]\pi[/itex]/2)+n[itex]\pi[/itex]=(2n+1/2)[itex]\pi[/itex]

    n=0,1,2,3....
    2. Relevant equations
    None.


    3. The attempt at a solution
    I have simplified the equation to this form, I just need help proving it.

    Thanks in advance.
     
  2. jcsd
  3. Aug 25, 2011 #2

    PAllen

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    I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?
     
  4. Aug 25, 2011 #3
    5[itex]\pi[/itex]/2=5[itex]\pi[/itex]/2
     
  5. Aug 25, 2011 #4

    PAllen

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    not with what you wrote in the initial post. Hard to help till you fix the OP.
     
  6. Aug 25, 2011 #5

    gb7nash

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    Homework Helper

    This statement is false. To reiterate what others have said, look at your previous work leading up to this point and try to find out where you made the error.
     
  7. Aug 25, 2011 #6
    Ah I found the problem.

    I figured it out, thanks for your help.
     
  8. Aug 25, 2011 #7

    Mark44

    Staff: Mentor

    Based on your first post, I don't see how you can get 5π/2 on the left side, when n = 1.

    To get 5π/2 on the left side, you would have to have (π + π/2) + π, but you have N + π + π/2. When N = 1, this is equal to 1 + π/3 (I'm using N because π ("pi") and n look almost the same).
     
  9. Aug 25, 2011 #8
    I used the equation on my paper. ( I put the wrong one on the OP by accident )

    Correct Equation is:

    (n[itex]\Pi[/itex]+[itex]\Pi[/itex]/2)+n[itex]\Pi[/itex]=(2n+1/2)[itex]\Pi[/itex]

    Which can be shown to be equal with some algebra.

    2n[itex]\Pi[/itex]+[itex]\Pi[/itex]/2=2n[itex]\Pi[/itex]+[itex]\Pi[/itex]/2

    Sorry for forgeting the pi in the OP :(.
     
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