Easy vector problem

  • Thread starter whizbang21
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  • #1
whizbang21
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1. A wall clock has a minute hand with a length of 0.45 m and an hour hand with a length of 0.23 m. Take the center of the clock as the origin, and use a Cartesian coordinate system with the positive x-axis pointing to 3 o'clock and the positive y-axis pointing to 12 o'clock. Find the displacements of the tip of each hand (that is, ΔAarrowbolditalic and ΔBarrowbolditalic) when the time advances from 3:00 P.M. to 6:00 P.M. (Aarrowbolditalic and Barrowbolditalic represent the tip of the hour hand and the tip of the minute hand, respectively.)

Let the +y direction be straight up and the +x direction be to the right. Recall the definition of displacement, and remember that positions are vector quantities.




Homework Equations


dont know, tried Pythagorean theorem.


The Attempt at a Solution


the part dealing with the minute hand is obviously 0. but as far as the hour hand, I've tried using the pythagorean theorem to calculate the displacement which would just be sqrt((.23^2)+(.23^2)^2) but apparently that was wrong, or maybe i just put the wrong sign. only have 1 more submission so not about to guess it.
 

Answers and Replies

  • #2
whizbang21
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halp
 
  • #3
cupid.callin
1,137
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can you calculate their angular displacements?
 

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