EC Air resistance problem.

  • Thread starter errubio
  • Start date
  • #1
2
0

Homework Statement



all information is on picture

Homework Equations





The Attempt at a Solution


I read the paper and understood it but when I got to the first question I was really confused. I do not even know what the problem is asking. This problem could give me an A in the class but its confusing the hell out of me. where did the e come from. If anyone can give me any hints or anything I would really appreciate it. I have worked on it for about 2 hours and I cannot figure it out. Please help
 

Attachments

Answers and Replies

  • #2
2
0
I end up with Vx=e^(-Yt) where Y=b\m
But i don't know where the cosine comes from for part 1
 
  • #3
sophiecentaur
Science Advisor
Gold Member
2020 Award
25,476
5,002
I end up with Vx=e^(-Yt) where Y=b\m
But i don't know where the cosine comes from for part 1
Are you familiar with adding vectors together and with splitting a vector into horizontal and vertical components?
 
  • #4
318
0
for the first part, where

V,x(t)=V0costheta(e^-gamma(t)) I would search up the true definition of e. I believe it has to do with taking the limit as n->infinity of (1 +r/n)^1/n, but I think I'm wrong. Once you gather this information, think about it's meaning and relate it to this problem to prove that this is true.
 
  • #5
318
0
oops I was close:
e = limn->infinity (1 + 1/n)^n.
http://mathforum.org/dr.math/faq/faq.e.html
where lets say you have V0 then V=V0(1+a/n)^nt if P=P0(1+r/n)^nt=P0(e^rt)due to the limit as n approaches infinity.

Don't quote me on this one, but just try to reason this analysis out to provide a thoughtful proof that makes logical sense.
 
  • #6
318
0
I'd then relate this analysis to euler's method. You know what that is right? I mean I hardly do, but this limit as n approaches infinity seems analogous to euler's method.
 

Related Threads on EC Air resistance problem.

Replies
5
Views
4K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
3
Views
963
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
5
Views
887
  • Last Post
Replies
10
Views
3K
  • Last Post
Replies
2
Views
4K
Replies
0
Views
3K
Replies
1
Views
2K
Top