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Using the average [EDTA], find the weight% of Ca2+ in the unknown

My attempt:

so, the[EDTA] i found from standardizing was 0.005 M;

I used 29.85mL to of EDTA to titrate my 25.00mL unknown

and the weight of my unknown used was 0.2505 g

this is what i did:

[EDTA] = 0.005M * 0.02985L = 1.489E-4 mol EDTA = mol Ca2+

so that is the moles of Ca2+ , my question is do I have to convert this moles to moles in 250mL, because the unknown was prepared in a 250mL volumetric flask, and only 25.00mL was taken out from that flask for titration. Does that mean 1.489E-4 moles (calculated above) is only the amount of moles in 25.00mL???????

any help appreciated :P