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Effect of inhibitor on enzyme

  1. Nov 25, 2008 #1
    [​IMG]

    I'm asked to calculate Vmax and KM from this, with and without the inhibior, and answer what kind of inhibitor it is.

    I have plotted 1/ vs 1/V0 here:

    [​IMG]

    The x-intercept is -1/KM. The value I get is -1/KM=-4E4, so that KM=25E-6. Does this mean that KM=25E-6 M? My book says 20-24 M. Of course, I might have been unaccurate in drawing the graph, but why do I miss by a factor of 1E6?
     
  2. jcsd
  3. Nov 25, 2008 #2

    epenguin

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    Maybe the book says (20-24)uM (micromolar)?

    But at your level I have some news for you, part bad part good.

    The bad news is sometimes books are wrong. Contain slips. Misprints. That the author does not pick up - can be quite hard to see when you read you own thing.

    The good news is you are sometimes right. :smile:
     
    Last edited: Nov 25, 2008
  4. Nov 25, 2008 #3
    Am I right this time?
     
  5. Nov 25, 2008 #4

    epenguin

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    Looks right to me.:approve: Of course I could be wrong.:biggrin:

    What is your answer to the other part of the question, type of inhibitor?
     
  6. Nov 25, 2008 #5
    Noncompetitive.
     
  7. Nov 25, 2008 #6

    epenguin

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    Right
     
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