# Effect of the Harmonic Oscilator Raising and Lowering Operators on Time Dependance

1. Aug 2, 2009

### rhysticlight

I am not really asking how to solve the problem but just for explanation of what I know to be true from the problems solution. Basically the original problem statement is this:

A particle in a harmonic oscillator potential starts out in the state
|psi(x,0)>=1/5 * [3|0> + 4|1>] and it asks to find the expectation value of position <x>.

Now the way I approached the problem was to first find |psi(x,t)> by simply "tacking on" the time dependent exponential terms and then expressing x through the ladder operators a+ and a-.

What I am wondering is when I, for example, apply the raising operator a+ to the state |0>*exp(-i*E0*t/h) does the function become |1>*exp(-i*E0*t/h) rather than |1>*exp(-i*E1*t/h) (i.e. why does the energy term in the time dependent part not change?)

Thanks!

2. Aug 2, 2009

### kuruman

Re: Effect of the Harmonic Oscilator Raising and Lowering Operators on Time Dependanc

The energy terms E1 and E0 are constants, namely multiples of $$\hbar$$$$\omega$$. Put in these values, if you wish, before you operate with the ladder operators and see what happens.

3. Aug 2, 2009

### rhysticlight

Re: Effect of the Harmonic Oscilator Raising and Lowering Operators on Time Dependanc

Ah o.k. I see now, thanks!