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Efficiency calculation

  1. Jun 30, 2010 #1

    I just saw something that is a bit confusing to me and i hope someone could explain the difference.
    I read something about an energy production system design and there are some calculations including some losses of the system. Taking into account the inverter losses, lets say for example 25% losses, in order to find the energy that must be produced, the energy is divided by 0.75.
    I dont know why divide with 0.75 instead of multiplying with 1.25 and what is the difference.

    Thanks in advance.
  2. jcsd
  3. Jul 1, 2010 #2
    Because efficiency = output energy / input energy
    You know losses = 25%=0.25 therefore output energy you get is only 75% (100%-25%). efficiency = 0.75.
    So if you want to find input energy output energy has to be divided by 0.75.
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