In one cycle, a heat engine absorbs 520J from the high-tempt reservoir and expels 390J to a low-tempt. reservoir. If the efficiency of this engine is 68% of the efficiency of a Carnot engine, what is the ratio of the low tempt. to the high tempt. in the Carnot engine? e=1-(390/520)=.25 Carnot engine e=.68*.25=.17 e=.25+.17=.42 .42=1-(Tl/Th) Tl/Th=1-.42=.58 Is this correct?