- #1
darw
- 3
- 0
Homework Statement
A 52-kg mountain climber, starting from rest, climbs a vertical distance of 730 m. At the top, she is again at rest. In the process, her body generates 4.1 × 10^10 J of energy via metabolic processes. In fact, her body acts like a heat engine, the efficiency of which is given by e = |W|/|QH|, where |W| is the magnitude of the work she does and |QH| is the magnitude of the input heat. Find her efficiency as a heat engine.
Homework Equations
e = |W|/|Q_H|
PE = mgh
Q_C = Q_H - W
The Attempt at a Solution
I calculated the potential energy gained by climbing the mountain. I called this Q, and called the 4.1 X 10 ^10 J the Work. However, this did not give me the correct efficiency. Could someone guide me toward what I am missing? Thanks so much for your time