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## Homework Statement

An 8.5 kg elevator is pulled at a constant velocity of 1.0 m/s by a 10.0 kW motor. Calculate the efficiency of the motor.

## Homework Equations

W = change in E = Fd

e = Work out/Work in * 100 = energy out/energy in *100

Epotential = mgh

Ekinetic = 1/2mv^2

P = W/t

## The Attempt at a Solution

Ekinetic = 1/2mv^2 = 8.5 J (Energy in)

I don't know how to get the Work from the motor as I don't have the time???