An 8.5 kg elevator is pulled at a constant velocity of 1.0 m/s by a 10.0 kW motor. Calculate the efficiency of the motor.
W = change in E = Fd
e = Work out/Work in * 100 = energy out/energy in *100
Epotential = mgh
Ekinetic = 1/2mv^2
P = W/t
The Attempt at a Solution
Ekinetic = 1/2mv^2 = 8.5 J (Energy in)
I don't know how to get the Work from the motor as I don't have the time???