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- Thread starter Shubha.Sagar
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HallsofIvy

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Of course, in the finite dimensional case, after we have chosen a basis, we can write a linear operator as a matrix, with each column showing what the operator takes each basis vector to (written in terms of that basis). If we choose an eigenvector, corresponding to eigen value [itex]\lambda[/itex] as the "n

If the vector space is a "function space", typically, infinite dimensional, we cannot write the operator as a matrix but still, using as many eigenvectors (eigen

As for the "physical significance"- like any question about the

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