- #1

eNtRopY

Are any of you nerds familiar with the

*Eigenvalue Condition*?

If so, please enlighten me.

eNtRopY

- Thread starter eNtRopY
- Start date

- #1

eNtRopY

Are any of you nerds familiar with the

If so, please enlighten me.

eNtRopY

- #2

jonnylane

There is a mathematical meaning, and i think it is pretty much the same thing i.e. mathematical operators in equations.

what was the context of the problem?

- #3

HallsofIvy

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"eigenvalue" equation is Ax= [lambda]x. x= 0 is a "trivial" solution. If there exist non-trivial (i.e. non zero) solutions [lambda] is an eigenvalue of A.

Physics: As "jonnylane" said, in quantum physics, various possible measurements (position, momentum) are interpreted as linear operators. The only possible specific numerical results of such measurements are eigenvalues of the linear operators. That may be what your inquirer was asking about.

- #4

eNtRopY

eNtRopY

- #5

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Most likely an eigenvalue boundary condition, though.

- #6

ahrkron

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The closest I can think of (as far as an "official" condition) would be the equationOriginally posted by eNtRopY

I think that the inquirer was asking about something else. I think that he meant something specifically related to the boundary value of a QM problem. I was just wondering if there was an officialEigenvalue Condition. I see now that there is not.

det(A-lambda I) == 0.

Which is used to determine the eigenvalues (lambda) of the linear operator A.

However, just as that, it has nothing to do with QM.

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