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Eigenvector of 2x2 matrix

  • Thread starter Ry122
  • Start date
for the matrix

when determining the eigenvector for its 2nd eigenvalue, -2, you would start out by doing

{5--2 ,0}
{2 ,-2--2}



In equation form this is

7u + 0v = 0
2u + 0v = 0

Ordinarily I would set u or v to a value and solve for the other letter.

But in this case this can't be done since in both equations v has a coefficient of 0.

So what would you do in this situation?


Science Advisor
Clearly u=0, and the equations will both be satisfied for any value of v, so the normalized eigenvector is (0,1).

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