# Eigenvectors and Eigenvalues

1. Apr 11, 2016

### DiamondV

1. The problem statement, all variables and given/known data
Find the eigenvalues and associated eigenvector of the following matrix:

2. Relevant equations

3. The attempt at a solution

We have a theorem in our lectures notes that states that if a matrix is invertible the only eigenvector in its kernel will be the zero vector. In order to find out if it is invertible we get the det(A) and see if its equal to 0 or not, if it is equal to 0(you cant divide by 0) then there is no inverse, if it is not equal to 0(like in this case I got 6) then it is invertible and the only vector is the zero vector in the kernel. So technically I should stop my calculations at this point and say the zero vector is the only one.
However in the solutions given to use they have an answer that is not a 0 vector.

1,2,3 are eigenvalues.
How is this possible?

2. Apr 11, 2016

### Ray Vickson

There is no such theorem as the one you state from your lectures. The zero vector is not considered as an eigenvector at all.

There is a theorem stating that if a matrix is invertible (has non-zero determinant) then the only vector (NOT EIGENVECTOR!) in the kernel is the zero vector. That has nothing at all to do with eigenvalues and eigenvectors.

Do you actually know what eigenvalues and eigenvectors are?

3. Apr 11, 2016

### DiamondV

Oh. Not really. Our lecture notes haven't shown any graphs with vectors on them or any sort of visualisation for this. I just know that theres these things called eigenvectors and eigenvalues that are really useful for some reason.