- #1
- 48
- 0
Then the proof goes on to consider coefficient of x viz a1=boc1 + b1co, and we know that a1=0modp and b1co=0modp so boc1=0modp.....
....2 questions why is b1co necessarily =0modp ? and secondly why does it follow that boc1=0modp? ....
.... i mean sure we know the sum b1co + boc1 =0modp but surely this doesn't imply b1co=0modp e.g 9=0mod3 but 9=5+4 and it is not true 5=0mod3
....2 questions why is b1co necessarily =0modp ? and secondly why does it follow that boc1=0modp? ....
.... i mean sure we know the sum b1co + boc1 =0modp but surely this doesn't imply b1co=0modp e.g 9=0mod3 but 9=5+4 and it is not true 5=0mod3
Last edited: