- #1
ATY
- 34
- 1
Hey guys, I got this problem:
We had the derivation of the ekman transport today in class. And what I wondered about is this:
Usually the equation for the ekman transport looks similar to this (depends on the author)
[tex] u = V_0 e^{az} cos(\frac{\pi}{4}+az) [/tex]
[tex] v = V_0 e^{az} sin(\frac{\pi}{4}+az) [/tex]
[tex] a= \sqrt{\frac{f}{2 A_z}} [/tex]
This is fine for the northern part of the earth, but what happens when I go to the southern hemisphere ? the coriolis parameter f should become negative (since f is [tex] f = 2 \Omega sin(\phi) [/tex])
So I can not use the equations above. I am really confused because none of the derivations that I found talked about this. Or am I missing a really obvious point ?
best wishes
ATY
We had the derivation of the ekman transport today in class. And what I wondered about is this:
Usually the equation for the ekman transport looks similar to this (depends on the author)
[tex] u = V_0 e^{az} cos(\frac{\pi}{4}+az) [/tex]
[tex] v = V_0 e^{az} sin(\frac{\pi}{4}+az) [/tex]
[tex] a= \sqrt{\frac{f}{2 A_z}} [/tex]
This is fine for the northern part of the earth, but what happens when I go to the southern hemisphere ? the coriolis parameter f should become negative (since f is [tex] f = 2 \Omega sin(\phi) [/tex])
So I can not use the equations above. I am really confused because none of the derivations that I found talked about this. Or am I missing a really obvious point ?
best wishes
ATY