Once again, I am pleading for help. Here is the problem and what I have done: Gayle runs at a speed of 4.00 m/s and dives on a sled, initially at rest, on the top of a frictionless, snow-covered hill. After she has descended a vertical distance of 5.00m, her brother, who is initially at rest, hops on her back and they continue down the hill together. What is the final velocity if the total vertical distance is 15.0 m? m1 = 50 kg m2 = 5 kg m3 = 30 kg I figure I have to solve for the first part, where the girl jumps on the sled and goes 5 m: KEi + PEi = KEf + PEf | | | | m1v1i +0 = m2v2f+mgh 50kg (4 m/s) = 55kg(v2f) + 55kg(9.8 m/s)(5 m) then: 200 = 55kg(v2f) + 2695 then, subtracting 2695 from the right & left: -2495 = 55kg (v2f) then, divide out the 55 from the right and then left: -45.36 = v2f I suppose the negative sign shows they are traveling down the hill. But then, assuming that my prior calculation is correct (which if it is, I want a ride on that sled), then I need to start over again except that my initial velocity would be v2f from the previous question, and I am looking for v3f, right? I hope this isn't too confusing, I'm trying to show that I've been working on this problem, and I would really like to understand it. Thank you for your help!