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Elastic collision between protons

  1. Oct 27, 2009 #1
    1. The problem statement, all variables and given/known data
    a proton with kinetic energy 10GeV collides with a proton at rest. 1 proton goes off with an angle of 45 degrees relative to the incoming proton. Find the velocity of both protons after the collison. This is an ellastic collision.
    E(initial) = 938 mev
    i honestly dont know where to start off but heres my attempts at a answer
    2. Relevant equations

    3. The attempt at a solution
    E=(MC^2)/(1-(v/c)^2)^1/2

    V/c= (1-((mc^2)/(E^2)))^1/2 V= .99632c


    V= v1 cos (30) + v2 cos(theta)
    v1 sin (30) + v2 sin (theta)
    E = E1 + E2
    10.938 gev = .938 gev/ (1-(v1/c)^2))^1/2 + .938gev/(1-(v2/c)^2)^1/2
    substitute and get the answer v1 is .00458
    and v2 is .49780
    however these answers dont work when put back into the equations..
     
  2. jcsd
  3. Oct 27, 2009 #2
    You forgot the gamma factors in the conservation of momentum equations.
     
  4. Oct 27, 2009 #3
    Also, you can solve the problem more easily using four-momentum algebra. You then only have to deal with one equation for hte energy of one proton after the collision, you don't have to consider a simultaneous set of equations for the energies and momenta of the two protons after the collision.
     
  5. Oct 27, 2009 #4
    four momentum algebra..? can u start me off with the equations?
    and also where have i missed the gamma..? because i cant seem to find it ..? unless my equations are wrong.
     
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