Elastic collision & Momentum

  • Thread starter Emendez3
  • Start date
  • #1
5
0
A proton (mass 1 u) is shot toward an unknown target nucleus at a speed of 2.40×10^6 m/s. The proton rebounds with its speed reduced by 25% while the target nucleus acquires a speed of 3.50×10^5 m/s.

What is the mass, in atomic mass units, of the target nucleus?




I tried:
Mp*Vip+Mn*Vin=Mp*Vfp+Mn*Vfn

where Mp= Mass proton=1
Vip= intial proton velocity=2.4E6
Mn= Mass nucleus=unknown
Vin=Initial Velocity of nucleus=0
Vfp= Final velocity proton=.75(2.4E6)
Vfn=final velocity nucleus= 3.5E5


i get 1.71u but its wrong
 

Answers and Replies

  • #2
367
0
The final proton velocity has a minus sign
 
  • #3
5
0
The final proton velocity has a minus sign

Thank you very much got the answer
 

Related Threads on Elastic collision & Momentum

  • Last Post
Replies
4
Views
9K
  • Last Post
Replies
3
Views
4K
  • Last Post
Replies
5
Views
10K
  • Last Post
Replies
1
Views
5K
P
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
13
Views
2K
Replies
2
Views
793
Replies
16
Views
1K
Replies
2
Views
4K
Replies
1
Views
1K
Top