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Elastic collision

  1. Apr 26, 2009 #1
    1. The problem statement, all variables and given/known data

    A 1 Kilogram object with speed of 2.0 m/s in the positive x direction has a head -on elastic collision with a stationary 0.70Kg object located at x=0. What acceleration does the stationary object experiences during the collision if the collision occurs over 0.2 seconds?


    2. Relevant equations

    m1v1i + m2v2i = m1v1f + m2v2f


    3. The attempt at a solution

    m1v1i + m2v2i = m1v1f + m2v2f
    (1)(2)+(0.7)(0)=(1)(v1f)+(0.7)(v2f)
    v1 +0.7 v2f = 2

    plug in:

    v1+0.7(2+v1)=2
    V1+ 1m +0.7 v1=2
    1.7=2-1.4
    1.7 v1=0.6
    v1=0.6/1.7 =0.353 m/s

    v2=2+0.353= 2.353 m/s

    m2(v2i-v2f)
    =0.7(2.353 -0)
    =1.6471=ft

    F=1.6471/t=1.6471/0.2=8.24N

    a=F/m = 8.24/1= 8.24 m/s^2 final answer

    Is this correct? Where did I go wrong? Do I have the everything in the right place?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Apr 26, 2009
  2. jcsd
  3. Apr 26, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Using conservation of momentum and energy find v2f. The rate of change of velocity will give you the acceleration of the stationary body.
     
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