Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Solving Elastic Collision: V1' = -2.5 m/s, 5.9 m/s
Reply to thread
Message
[QUOTE="KoaDcT, post: 5492866, member: 596222"] [h2]Homework Statement [/h2] The problem is pretty simple, however I don't understand which value to use after using quad formula to solve. See below. V1(initial) = 2.5 m/s V2(Initial) = -5.9 m/s A pool ball moving with a speed of 2.5 m/s makes an elastic head-on collision with an identical ball traveling in the opposite direction with a speed of 5.9 m/s. Find the velocities of the balls after the collision. [h2]Homework Equations[/h2] ΣP(initial) = ΣP(final) M[SUB]1[/SUB]V[SUB]1[/SUB] + M[SUB]2[/SUB]V[SUB]2[/SUB] = M[SUB]1[/SUB]V[SUB]1[/SUB]' + M[SUB]2[/SUB]V[SUB]2[/SUB]' M[SUB]1[/SUB] = M[SUB]2[/SUB] 2.5 + (-5.9) = V[SUB]1[/SUB]' + V[SUB]2[/SUB]' V[SUB]2[/SUB]' = -V[SUB]1[/SUB]' - 3.4 Elastic collision: KE(initial) = KE(final) (Mass cancels out) V[SUB]1[/SUB][SUP]2[/SUP]+V[SUB]2[/SUB][SUP]2[/SUP] = V[SUB]1[/SUB]'[SUP]2[/SUP]+V[SUB]2[/SUB]'[SUP]2[/SUP][h2]The Attempt at a Solution[/h2] From above, I got: 0 = 2V[SUB]1[/SUB]'[SUP]2[/SUP] - 6.8V[SUB]1[/SUB]' - 29.5 by substituting "V[SUB]2[/SUB]' = -V[SUB]1[/SUB]' - 3.4" for V[SUB]2[/SUB]' After applying quadratic equation I got: V[SUB]1[/SUB]' = -2.5 m/s, 5.9 m/s My problem is I do not know which one is the correct answer. My answer key says V[SUB]1[/SUB]' is equal to -2.5 m/s, but I have no idea why. Any help is appreciated! [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Solving Elastic Collision: V1' = -2.5 m/s, 5.9 m/s
Back
Top