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A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?

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A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?

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How did you get your answer?

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I got my answer by using M*Vi=M*Vf

Last edited:

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Eminem04: Yes, your answer is completely correct. Since the two balls have the same mass and one stopped completely, the other continues forward with the same speed as the initial ball. (In a sense, it just "replaces" the first ball.)

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