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My problem is:

An electron( mass m=9.11 x 10^-31 kg) is accelerated in the uniform field E( E=1.45 x 10^4 N/C) between two parallel charged plates. The seperation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate. With what speed does it leave the hole?

Work

m=9.11 x 10^-31 kg

E=1.45 x 10^4 N/C

distance= 1.10 x 10^.2 m

q= -1.6 x 10^-19 C

qE(s) = ½ mv^2 - ½ mv^2

-1.6 x 10^-19 C= ½ (9.0 x 10^-31 kg)(v)^2

solve for v

v=7.14 x10^-7 m/s

Is this the correct way of approaching the problem, or answer?

Please help

Thank You

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