- #1

jgens

Gold Member

- 1,581

- 50

## Homework Statement

A 300 MW power station produces electricity at 80 kV which is then supplied to consumers along cabes of total resistance 5.0 ohms. What percentage of the power is lost in the cables.

## Homework Equations

P = VI = V

^{2}/R

## The Attempt at a Solution

I said the total power was P

_{T}= 300 MW

Power dissipated in the cables: P

_{d}= V

^{2}/R = (80 kV)

^{2}/(5.0 ohms) = 1280 MW

This didn't make any sense because that power dissipated exceeds the power produced. So here's another attempt:

Power remaining: P

_{R}= 300 MW

Power dissipated: P

_{D}= V

^{2}/R = (80 kV)

^{2}/(5.0 ohms) = 1280 MW

Total Power: P

_{T}= P

_{R}+ P

_{D}= (1280 + 300) MW = 1580 MW

Percentage Lost: P

_{D}/P

_{T}= 1280/1580 = 81.0%

I'm not sure if this is right but it's my best guess. Any help is appreciated. Thanks.

Last edited: