1. The problem statement, all variables and given/known data A 300 MW power station produces electricity at 80 kV which is then supplied to consumers along cabes of total resistance 5.0 ohms. What percentage of the power is lost in the cables. 2. Relevant equations P = VI = V2/R 3. The attempt at a solution I said the total power was PT = 300 MW Power dissipated in the cables: Pd = V2/R = (80 kV)2/(5.0 ohms) = 1280 MW This didn't make any sense because that power dissipated exceeds the power produced. So here's another attempt: Power remaining: PR = 300 MW Power dissipated: PD = V2/R = (80 kV)2/(5.0 ohms) = 1280 MW Total Power: PT = PR + PD = (1280 + 300) MW = 1580 MW Percentage Lost: PD/PT = 1280/1580 = 81.0% I'm not sure if this is right but it's my best guess. Any help is appreciated. Thanks.