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Electric Charge of a proton

  • Thread starter Whatupdoc
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99
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A proton is on the x-axis at x= 1.6nm. An electron is on the y-axis at y=0.85nm. Find the net force the two exert on a helium nucleus (charge + 2e) at the orgin.

there's a solution from the book, but i dont really understand it:
k = 9X10^9 N*m^2 and e=1.6*10^-19

Coulomb force of the proton on the helium nucleus is F_pHe = k(e)(2e)(-i)/(1.6mm)^2 = -0.180i*nN (i get 1.8X10^-28 instead)

for the y:
FeHe= k(-e)(2e)(-j)/(.85nm)^2 = 0.638j nN (i get 6.377 X 10^-28)

the answer would be -0.180i*nN + 0.638j nN right? i just dont know why my numbers are so small
 
Last edited:

Answers and Replies

ehild
Homework Helper
15,361
1,778
Whatupdoc said:
A proton is on the x-axis at x= 1.6nm. An electron is on the y-axis at y=0.85nm.
there's a solution from the book, but i dont really understand it:
k = 9X10^9 N*m^2 and e=1.6*10^-19
Coulomb force of the proton on the helium nucleus is F_pHe = k(e)(2e)(-i)/(1.6mm)^2 = -0.180i*nN (i get 1.8X10^-28 instead)....
i just dont know why my numbers are so small

The distances given was in nm-s (10^-9 m) but you used mm-s (10^-3). or you even have forgotten that 10^-3, too.

ehild
 
99
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(9X10^9 N*m^2)(1.6*10^-19)(2(1.6*10^-19))(-i)/(1.6mm)^2 = 1.8X10^-28

right? i did use 10^9
 
lightgrav
Homework Helper
1,248
30
no, for the distance you just used 1.6 m .
enter the distance into your calculator as (1.6E-9 [m])^2

and be sure to use the EXP button (or EE button) ,
NOT the ambiguous sequence / 1.6 x 10 ^-9 ^2 !
 

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