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Whatupdoc

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A proton is on the x-axis at x= 1.6nm. An electron is on the y-axis at y=0.85nm. Find the net force the two exert on a helium nucleus (charge + 2e) at the orgin.

there's a solution from the book, but i don't really understand it:

k = 9X10^9 N*m^2 and e=1.6*10^-19

Coulomb force of the proton on the helium nucleus is F_pHe = k(e)(2e)(-i)/(1.6mm)^2 = -0.180i*nN (i get 1.8X10^-28 instead)

for the y:

FeHe= k(-e)(2e)(-j)/(.85nm)^2 = 0.638j nN (i get 6.377 X 10^-28)

the answer would be -0.180i*nN + 0.638j nN right? i just don't know why my numbers are so small

there's a solution from the book, but i don't really understand it:

k = 9X10^9 N*m^2 and e=1.6*10^-19

Coulomb force of the proton on the helium nucleus is F_pHe = k(e)(2e)(-i)/(1.6mm)^2 = -0.180i*nN (i get 1.8X10^-28 instead)

for the y:

FeHe= k(-e)(2e)(-j)/(.85nm)^2 = 0.638j nN (i get 6.377 X 10^-28)

the answer would be -0.180i*nN + 0.638j nN right? i just don't know why my numbers are so small

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