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Electric Charge of a proton

  1. Aug 29, 2005 #1
    A proton is on the x-axis at x= 1.6nm. An electron is on the y-axis at y=0.85nm. Find the net force the two exert on a helium nucleus (charge + 2e) at the orgin.

    there's a solution from the book, but i dont really understand it:
    k = 9X10^9 N*m^2 and e=1.6*10^-19

    Coulomb force of the proton on the helium nucleus is F_pHe = k(e)(2e)(-i)/(1.6mm)^2 = -0.180i*nN (i get 1.8X10^-28 instead)

    for the y:
    FeHe= k(-e)(2e)(-j)/(.85nm)^2 = 0.638j nN (i get 6.377 X 10^-28)

    the answer would be -0.180i*nN + 0.638j nN right? i just dont know why my numbers are so small
     
    Last edited: Aug 29, 2005
  2. jcsd
  3. Aug 29, 2005 #2

    ehild

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    The distances given was in nm-s (10^-9 m) but you used mm-s (10^-3). or you even have forgotten that 10^-3, too.

    ehild
     
  4. Aug 29, 2005 #3
    (9X10^9 N*m^2)(1.6*10^-19)(2(1.6*10^-19))(-i)/(1.6mm)^2 = 1.8X10^-28

    right? i did use 10^9
     
  5. Aug 29, 2005 #4

    lightgrav

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    no, for the distance you just used 1.6 m .
    enter the distance into your calculator as (1.6E-9 [m])^2

    and be sure to use the EXP button (or EE button) ,
    NOT the ambiguous sequence / 1.6 x 10 ^-9 ^2 !
     
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