Electric charge is distributed uniformly along a thin rod of length a, with total charge Q. Take the potential to be zero at infinity. Find the potential at the following points: P is distance x from (0,0) which is the right side of the rod.(adsbygoogle = window.adsbygoogle || []).push({});

Find the potential at the point P, a distance to the right of the rod.

already answered

In part A, what does your result reduce to as x becomes much larger than a?

answer from A.

Q/a4pi(e0)(ln(x+a)-ln(x)

So as x becomes larger than a, (moves toward infinity)V should reduce to zero. The ln's should cancel eachother out, leaving you to multiply by 0. Except 0 is not excepted.

Ive tried

KQ(ln(x)-ln(x))

0

KQ0

According to the software, the answer depends on x, and does not depent on a.

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# Electric charge of a thin rod

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