Hey. I am trying to solve the following problem:(adsbygoogle = window.adsbygoogle || []).push({});

Given a spherical shell with radius a and charge density sigma. If a very small patch of this surface were removed, leaving a small hole, what is the electric field just above and just below this hole?

For the electric field below the hole, I think the answer is zero, by gauss' law. Since the charge enclosed would be zero (same as if the hole were not present).

However, I'm not sure how I would go about solving for the electric field above the hole. I initially thought that I could simply calculate what the field would be if the hole was not there, and then take this result and subtract the electric field of a small disk of radius a (that would represent the hole) but I don't seem to get the right answer.

And help would be appreciated! Thanks!

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# Homework Help: Electric Charge Problem

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