Hello! i'm just preparing to write my physics 12 final and can't seem to solve a problem form a past exam that i was doing(adsbygoogle = window.adsbygoogle || []).push({});

Here is the question:

a circuit using a new battery which has an emf of 6.00 V and an internal resistnace of 1.00 ohms is shown on the left( In the diagram there also is a current of 0.375 A and a resistor place in series labeled R)

THe battery is then replaced with a used one that has the same emf of 6.00 V bu ta different internal resistance.

If resistor R now dissipates 1.75 W, waht is the internal resistance of the used battery??????????

(diagram the same but with 1.75 W at the R (resistor in series placed in circuit)

THe answer is 2.57 ohms

i tryed using Vterminal =6.00- (.375)(1) in regards to the orginal battery

and v terninal is then equal to 5.625

You then need to figure out I in the next situiation i'm assuming using Power. P=IV... i dunno i got lost and tryed to work backwards but no dice

any help woudl be awesome

email me at liajohnson55@hotmail.com

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# Electric Circuit Problem - Help Asap Final In 3 Days

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