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Electric circuit

  1. Aug 2, 2006 #1

    find the current I(B) by calculation

    Use the current function and KVL
    the function is given as I(B)=0.01 (V(B) - 0.65V)^2

    Can somebody pls show me the KVL ??
    i tried to write the KVL as V(i) - I(B)R(i) - V(B) =0
    then substitute into the function but doesn't work.

    pls help
  2. jcsd
  3. Aug 2, 2006 #2


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    Staff: Mentor

    The attachment didn't work for me -- all I got was some pop-up ads and the Savefile home page or something. Can you upload it or post it somewhere else?
  4. Aug 2, 2006 #3
  5. Aug 2, 2006 #4


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    Staff: Mentor

    Still lots of popus and no circuit diagram. Try saving it as a pdf or jpg and uploading it to PF. If you need a free PDF writer, to to PrimoPDF.com.
  6. Aug 3, 2006 #5
    nono,just download the file.there is a link at the bottom which u need to click on it to download

    i have tried
  7. Aug 3, 2006 #6
    What is the answer?
  8. Aug 3, 2006 #7
    the answer is 2.781mA
    Can u solve it??
    pls teach me...
    thanx very much
  9. Aug 3, 2006 #8
    sorry,actually it is given that I(c) = 150 I(B)
    so the answer for the I(c) is 2.781mA
  10. Aug 3, 2006 #9


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    Staff: Mentor

    Ahhh, click the link next to the red flashing arrow thing. Got it. What are the values of Vi, Ri, Vo and R? You need those to get anywhere with the calculation. And where did that equation come from that you gave in your first post?

  11. Aug 3, 2006 #10
    the equation is given in the answer.anyway,how do u write the KVL loop eqn??
    i just want to know how do u write it pls

  12. Aug 3, 2006 #11
    Your equation describing the loop is perfect and it works. Please tell us in detail in what way does it not work for you?

    You meant


    Last edited: Aug 3, 2006
  13. Aug 3, 2006 #12
    Unless I am missing something here, I don't think you can find a value for IB unless you know the values of Vi, Ri and the rest.

    Please state the question in full.
  14. Aug 4, 2006 #13
    okok.....i have the values

    thank you
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