A 500 ohm resistor and a 1000 ohm resistor are connected in series with a 12 V battery of negligible internal resistance . When a voltmeter is connected across the 500 ohm resistor , its reading is 3 V . What is the resistance of the voltmeter ?
The Attempt at a Solution
the effective resistance across the voltmeter and 500 ohm resistor (i am not sure across which) is Re=500Rm/(500+Rm) where Rm= resistance of meter and Re=effective resistance
From V=IR , 12=I(1500) , so the current flowing through the circuit is 0.008 A .
solving this , Rm=1500 ohm
but the answer given is 1000 ohm , i wonder where have i gone wrong