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Electric Current Problem

  1. Nov 30, 2014 #1
    1. The problem statement, all variables and given/known data
    Two 16 Ohm resistors connected in parallel are then connected in series to a 10 Ohm resistor. The entire setup is connected to a 9 V battery. What is the current through the 10 Ohm resistor?

    2. Relevant equations
    V=IR
    I1+I2=It
    1/Rt= 1/R1 + 1/R2

    3. The attempt at a solution

    So im not sure if i am correct. If the two 16 ohm resistors were connected parallel, then wouldnt their overall resistance be 8 ohm because 2(1/16)= 1/8 which 8 is Rtotal? Then after you find Rtotal you add it to the 10 ohm resistor to get a total resistance of 16 ohm. From this, you can solve using the equation V=IR. Plug in 9 for V and 16 for R and you end up getting I= 0.5 . Is this the correct answer and is my approach correct? Thanks for the help everyone!
     
  2. jcsd
  3. Nov 30, 2014 #2

    haruspex

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    Right.
    Wrong.
     
  4. Nov 30, 2014 #3
    How do I get the overall resistance?
     
  5. Nov 30, 2014 #4

    haruspex

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    By adding the resistances correctly. 8+10=?
     
  6. Nov 30, 2014 #5
    Oh yes that is what I meant, bad addition. So is the rest of the way I used to solve this problem correct?
     
  7. Nov 30, 2014 #6

    haruspex

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    Yes.
     
  8. Nov 30, 2014 #7
    Thank you so much!
     
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