1. The problem statement, all variables and given/known data Two 16 Ohm resistors connected in parallel are then connected in series to a 10 Ohm resistor. The entire setup is connected to a 9 V battery. What is the current through the 10 Ohm resistor? 2. Relevant equations V=IR I1+I2=It 1/Rt= 1/R1 + 1/R2 3. The attempt at a solution So im not sure if i am correct. If the two 16 ohm resistors were connected parallel, then wouldnt their overall resistance be 8 ohm because 2(1/16)= 1/8 which 8 is Rtotal? Then after you find Rtotal you add it to the 10 ohm resistor to get a total resistance of 16 ohm. From this, you can solve using the equation V=IR. Plug in 9 for V and 16 for R and you end up getting I= 0.5 . Is this the correct answer and is my approach correct? Thanks for the help everyone!