1. The problem statement, all variables and given/known data An ammonia molecule (NH_3) has a permanent electric dipole moment 5.0 * 10^-30 Cm . A proton is 2.50 nm from the molecule in the plane that bisects the dipole. What is the electric force of the molecule on the proton? 2. Relevant equations E_dipole = K 2p / r^3 (on axis of electric dipole) E_dipole = -K p / r^3 (in the plane perpendicular to an electric dipole) E_dipole = (F on q) / q 3. The attempt at a solution p = 5.0E-30 Cm r = 2.50E-19 m Use second equation because the question implies its perpendicular to the electric dipole of ammonia? q of proton = q_p = 1.60E-19 C F_(molecule on proton) = F = E_dipole * | q of proton | F = [-K * (p / r^3)] * |q_p| F = [(-9.00E9) * (5.0E-30) / (2.5E-9)^3)] * 1.60E-19 F = -4.60E-13 N Help would be awesome!