Electric Field and Potential on a Line with Opposite Charges

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In summary, a positive charge of +q is located 3.00m to the left of a negative charge -q2. The net electric field is zero at a spot 1.00m to the right of the negative charge, and there are two spots on this line where the potential is also zero. By setting the E field due to the positive charge equal to the E field due to the negative charge and solving for the magnitude of Q2, we can locate the two spots where the potential is zero relative to the negative charge. We can also use this information to find the position of any point x on the line through the charges by setting the sum of the potentials due to each charge equal to zero and solving for x.
  • #1
silver_gry
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Homework Statement


A positive charge of +q is located 3.00m to the left if a negative charge -q2. The charges have different magnitudes. On the line through the charges, the net electric field is zero at a spot 1.00m to the right of the negative charge. On this line there are also two spots where the potential is zero. Locate these 2 spots relative to the negative charge.


Homework Equations



I don't know which equation I should use to start with. I really need help with this question.

The Attempt at a Solution

 
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  • #2
At the point where E = 0, the E field due to the positive charge is equal (and opposite) to the E field due to the negative charge. Write this, replace each E with the formula for E, put in the numbers for the distance. You will end up with Q1 = a number times Q2.

Now pick a point x on the line through the charges. Say, x meters to the right of Q1. Write the expression for the potential there - the sum of the potentials due to each charge. Use the multiple of Q1 in place of Q2 so the Q1 cancels out in this equation. You should be able to solve it and find x.
 
  • #3


I would first identify the given information and variables in the problem. The given information includes the presence of two opposite charges (+q and -q2) on a line, with the positive charge located 3.00m to the left of the negative charge. The problem also states that on this line, there is a point 1.00m to the right of the negative charge where the net electric field is zero, and two points where the potential is also zero.

To solve this problem, I would use the equation for electric field: E = kq/r^2, where k is the Coulomb's constant, q is the magnitude of the charge, and r is the distance between the charges. Using this equation, I can calculate the electric field at the point 1.00m to the right of the negative charge, and then use it to determine the magnitude of the positive charge q.

Next, I would use the equation for electric potential: V = kq/r, where V is the potential, k is the Coulomb's constant, q is the magnitude of the charge, and r is the distance between the charges. Using this equation, I can calculate the potential at the two points where it is zero, and then use it to determine the distance between these points and the negative charge, as well as the magnitude of the positive charge q.

In summary, as a scientist, I would approach this problem by using the equations for electric field and potential to calculate the unknown variables and solve for the two points where the potential is zero relative to the negative charge. This would allow me to fully understand the behavior of the electric field and potential on a line with opposite charges.
 

1. What is an electric field?

An electric field is a force field that surrounds an electrically charged object. It is created by the interaction of positive and negative charges and can exert a force on other charged objects within its vicinity.

2. How is an electric field measured?

An electric field is measured in units of volts per meter (V/m). This unit represents the strength of the electric field at a particular point in space. The direction of the electric field can also be measured, and it is represented by the direction in which a positive test charge would move if placed in the field.

3. What factors affect the strength of an electric field?

The strength of an electric field is affected by the magnitude of the charges creating the field, as well as the distance between them. The closer the charges are, the stronger the field will be. Additionally, the type of material the charges are located in can also affect the strength of the electric field.

4. How does an electric field interact with matter?

An electric field can interact with matter in a few different ways. It can cause charges to move within a material, which can create a current. It can also cause polarization, where the charges within a material are aligned in a certain direction. Finally, it can exert a force on charged particles within a material, causing them to accelerate or change direction.

5. How is an electric field used in everyday life?

Electric fields have many practical applications in our daily lives. They are used in electronic devices such as computers, televisions, and cell phones to transfer and manipulate charges. Electric fields are also used in medical equipment, such as MRI machines, to create images of the body. Additionally, electric fields are used in power plants to generate and distribute electricity for our homes and businesses.

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