Hey guys was wondering if anyone could help me out :)(adsbygoogle = window.adsbygoogle || []).push({});

Question))A Positive Charge Q is uniformly distributed around a semicircle of radius a. Find the electric field(magnitude and direction) at the center of curvature P.

Basically it looks like a unit circle except the radius is A and we need to calculate the electric field at point P which is at the origin.

This is the approach I took but it is wrong.

DE=2(pi)(k)(a)(dQ)/(x^2+a^2)^(3/2)

And when I integrated it, I came to 2(pi)(k)(Q)/a^2 for the electric field

I am not sure...

The right answer is 2(k)(Q)/((pi)(a^2))

Can anyone help me ??

Thanks alot everyone

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# Homework Help: Electric Field and curvature

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