1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electric Field and Electric Potential

  1. Jun 7, 2004 #1
    A charge of -10 microcoulumbs is located at the origin of an x-y coordinate system. Another charge of -10 microcoulumbs is located at the point (0, 2.0 m). Determine the electric field and the electric potential at the point (0, 1.0 m).

    Here is what I did. Is this the correct way?

    E1 = (9*10^9) (10*10^-6)/1^2 = 90,000 N/C
    E2 = (9*10^9) (10*10^-6)/1^2 = 90,000 N/C
    Etotal = 90,000 - 90,000 = 0 (Electric field)

    V1 = (9*10^9) (-10*10^-6)/1^2 = -90,000 V
    V2 = (9*10^9) (-10*10^-6)/1^2 = -90,000 V
    Vtotal = -90,000 + -90,000 = -180,000 V (Electric potential)
     
  2. jcsd
  3. Jun 7, 2004 #2
    help!

    Please reply ASAP. I have an exam in about 10 hours! :eek:
     
  4. Jun 8, 2004 #3

    Gza

    User Avatar

    It's correct. You should post at the k-12 board next time though.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Electric Field and Electric Potential
Loading...