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Homework Help: Electric Field and Electric Potential

  1. Jun 7, 2004 #1
    A charge of -10 microcoulumbs is located at the origin of an x-y coordinate system. Another charge of -10 microcoulumbs is located at the point (0, 2.0 m). Determine the electric field and the electric potential at the point (0, 1.0 m).

    Here is what I did. Is this the correct way?

    E1 = (9*10^9) (10*10^-6)/1^2 = 90,000 N/C
    E2 = (9*10^9) (10*10^-6)/1^2 = 90,000 N/C
    Etotal = 90,000 - 90,000 = 0 (Electric field)

    V1 = (9*10^9) (-10*10^-6)/1^2 = -90,000 V
    V2 = (9*10^9) (-10*10^-6)/1^2 = -90,000 V
    Vtotal = -90,000 + -90,000 = -180,000 V (Electric potential)
     
  2. jcsd
  3. Jun 7, 2004 #2
    help!

    Please reply ASAP. I have an exam in about 10 hours! :eek:
     
  4. Jun 8, 2004 #3

    Gza

    User Avatar

    It's correct. You should post at the k-12 board next time though.
     
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