# Electric field and gaussian surface

1. May 26, 2004

### PinkFlamingo

A small copper spherical BB of radius a is located at the center of a larer hollow copper spherical shell of inner radius b and outer radius R. A charge of +q is on the small BB. The hollow copper shell has zero charge on it.

a) What is the electric field within the BB (for radii r<a)?

b) What is the electric field inside the copper shell (for radii that stisfy b<r<R)

c) Draw a closed Gaussian surface within the copper of the shell. What is the total flux of the electric vector through this Gaussian surgace? This result implies that charge must lie on the inside surface of the spherical shell. What charge must reside on the inside surgface of the copper shell? Since the copper shell has a total charge of zero, what charge must reside on the outer surface of the copper shell?

So far all I've been able to figure out is that the answer to b is 0 I think???

Last edited: May 26, 2004
2. May 26, 2004

### Staff: Mentor

These questions require you to know two things:
(1) The electrostatic field within a conductor is zero
(2) Gauss's Law, which relates the total electric flux through a closed surface to the charge within that surface

Can you state Gauss's Law? How do you apply it?

3. May 26, 2004

### PinkFlamingo

Would the answer to a AND b be 0 because they're both within the conductor?

4. May 26, 2004

### Staff: Mentor

Yes. The field within both conductors is zero.

5. Jun 2, 2004

### PinkFlamingo

Would the answer to c be 0 as well, since the total charge is 0, the flux must be 0 too right?

6. Jun 2, 2004