Suppose that H2O molecule (micro = 1.85 D) approaches an anion (such as Cl-) in the gas phase (situation typical of the ion-induced nucleation of atmospheric water vapor). (a) What is the favorable orientation of a molecule? (b) Calculate the electric field (in V/m) experienced by the anion when water dipole is 1.0 nm from the ion. 2. Relevant equations I don't know if it is relevant but I think this must be used maybe E=F/q or E=K * Q/d^2 where K is a constant of 9.0x10^9 N * m^2/C^2 and Q is electric force and d is distance between the two objects 3. The attempt at a solution Okay so I don't know if this is right but this my guess E= (9.0x10^9 * 1.85)/(1.0x10^-9)^2 = 1.67x10^28 N*D/C^2 I know this is not the right units and that to get voltage i need to have N*m/C that then equals joules/C that =voltage. I am just very confused and any help would be great. I am not exactly sure what it means by orientation like if is talking about the geometry of the molecule or if it should be drawn out with the hydrogen bonds on the water molecule facing towards the anion.