Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts.
a. What is the electric field strength between them, if the potential 6.65 cm from the zero volt plate (and 3.35 cm from the other) is 633 V?
b. What is the voltage between the plates?
V = Ed
The Attempt at a Solution
For a I got 9.5 keV which was from the formula: (633V)/0.0665m = 9.5eV E3.
For b I don't know what to do? The electric field is uniform so the electric field is just 9.5E3 and the distance will be 10cm/2 = 5 cm. But how can I get the correct answer?