# Electric Field due to two circular line charges

blue_leaf77
Homework Helper
Look for something like ##\hat{r} = \ldots \hat{x} + \ldots \hat{y} + \ldots \hat{z}##.

Yeah so:

##\hat{r}=cos{\theta}sin\phi\hat{x}+sin{\theta}cos\phi\hat{y}+cos\phi\hat{z}##

blue_leaf77
Homework Helper
No, check again whether you copied it right.

Sorry dunno how I did that:

##\hat{r}=sin{\theta}cos\phi\hat{x}+sin{\theta}sin\phi\hat{y}+cos\phi\hat{z}##

blue_leaf77
Homework Helper
Now put that into the integral in comment #44 and do the integration, remember the integration variable is ##\phi## while ##\theta## is a constant (I leave to you to express the sine or cosine of ##\theta## in terms of known quantities). You should find that there are only two components surviving the integration. Upon considering (no calculation is needed) the contribution from the other half of the ring, one more component should vanish, and the only remaining components should be enhanched by a factor of two. Good luck.

Quick question, those the upper limit stay as ##\phi##? Thanks for all the help with this question, hopefully it all pays off.

blue_leaf77
Homework Helper
That's a mistake, see again I have corrected it.

What I end up with is:

##E_+=\frac{Q}{2\pi\epsilon_0} \frac{1}{\sqrt{a^2+z^2}}##

Is this the answer I should've gotten?

blue_leaf77