Identical thin rods of length (2a) carry equal charges +Q uniformly distributed along their lengths.(adsbygoogle = window.adsbygoogle || []).push({});

The rods lie on (along) the x axis with their *centers* separated by a distance b > 2a.

(Left rod from x=-a to x=a, right rod from x=b-a to x=b+a)

Show that the magnitude of the force exerted by the left rod on the right one is

[tex]F = k_e\frac{Q^2}{4a^2} \ln \frac{b^2}{b^2-4a^2}[/tex]

Thanks very much for answering :-)

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# Homework Help: Electric Field/Force btw rods

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