• Support PF! Buy your school textbooks, materials and every day products Here!

Electric Field Help Please

  • #26
gneill
Mentor
20,781
2,759
How do I find the acceleration then, I'm missing the force
You don't need to find a particular value for the force. You just need to find an expression for it, and note what values it depends on, and whether or not any of them differ from case to another in your problem.
 
  • #27
18
2
You don't need to find a particular value for the force. You just need to find an expression for it, and note what values it depends on, and whether or not any of them differ from case to another in your problem.
What differs in the problem is their distance maybe, their velocities and their direction. Other than that I assume their acceleration since thats what we are looking for.
 
  • #28
gneill
Mentor
20,781
2,759
What differs in the problem is their distance maybe, their velocities and their direction. Other than that I assume their acceleration since thats what we are looking for.
That's why you need to write an expression for the acceleration, so you can test your assumptions.
 
  • #29
18
2
That's why you need to write an expression for the acceleration, so you can test your assumptions.
So like Acceleration,=??? meters/s^2 Q=1.6x10^-19 C, m=1.67x10^-27kg, E=?????? N/C, F=???? Newtons,
a=F/m
F= QxE
a=(QxE)/m
Only problem is there is nothing about direction or velocity
 
  • #30
gneill
Mentor
20,781
2,759
So like Acceleration,=??? meters/s^2 Q=1.6x10^-19 C, m=1.67x10^-27kg, E=?????? N/C, F=???? Newtons,
a=F/m
F= QxE
a=(QxE)/m
Only problem is there is nothing about direction or velocity
That's not a problem, it's a bonus and a clear result! You now now that the acceleration does not depend upon direction or speed or distance; It only depends on the charge, the mass, and the electric field. So what can you conclude for the different cases presented?
 
  • #31
18
2
That's not a problem, it's a bonus and a clear result! You now now that the acceleration does not depend upon direction or speed or distance; It only depends on the charge, the mass, and the electric field. So what can you conclude for the different cases presented?
Their accelerations are the same?? That just doesn't seem like him. (professor)
 
  • #32
gneill
Mentor
20,781
2,759
Their accelerations are the same?? That just doesn't seem like him. (professor)
Yes, the accelerations are all identical. It is the correct result for the question in the form it was given.

The question may seem like a trick, or perhaps it is incorrect due to a typo or otherwise, yet even so it got you to think about the physics of the situation.
 
  • #33
18
2
Ok thanks gneill and berkeman. I guess you guys had said their accelerations were same in the beginning but it definitely helped figuring out why. I''ll talk to my professor tomorrow and I think it's actually due Tuesday so if theres something I'm missing I'll bring it up tomorrow?

Thanks!!
 
  • #34
gneill
Mentor
20,781
2,759
Ok thanks gneill and berkeman. I guess you guys had said their accelerations were same in the beginning but it definitely helped figuring out why. I''ll talk to my professor tomorrow and I think it's actually due Tuesday so if theres something I'm missing I'll bring it up tomorrow?
That would be fine!
Thanks!!
You're very welcome.
 

Related Threads for: Electric Field Help Please

Replies
0
Views
4K
  • Last Post
Replies
1
Views
8K
Replies
2
Views
37K
Replies
3
Views
1K
Replies
14
Views
11K
  • Last Post
Replies
4
Views
599
  • Last Post
Replies
9
Views
6K
Top