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**Electric Field Help! SIMPLE problem!**

## Homework Statement

Two particles are fixed to an x axis: particle 1 of charge -3.50*10-7 C at x = 6.00 cm, and particle 2 of charge +3.50*10-7 C at x = 29.0 cm. Midway between the particles, what is their net electric field?

## Homework Equations

Fe= KQ1Q2 / R^2

## The Attempt at a Solution

Fe= (8.99E9)(-3.50E-7)(3.50E-7) / (11.5^2)

Fe= 8.33E-6

Okay just to let you know i got 11.5 for R by doing (29-6) / 2 because the question asks what is teh net charge between teh two particles, but when i put the answer in it came wrong even when i did and didnt put the negative sign.

so then i decided to do (29+6) / 2 and i got 17.5 and i used that for R but the answer was still wrong. my answer was -3.597E-6. i typed this answer in with the negative sign and without it, but it was still wrong.

I HAVE aTTACHED A picture of my Free-Body DIAGRAM!

i don't know what to do from here, can anyone please guide me/help me? THANKs!

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