Electric field help

1. Aug 21, 2005

arutha

I have these questions on electric fields that I'm a bit confused on..

A flat circle of radius 8 cm is placed in a uniform electric field of 8.5 × 10^2 N/C. What is the electric flux (in Nm^2/C) through the circle when its face is at 51° to the field lines?

I just use EAcos(theta) don't I? Where A is 2*pi*r, but that angle do I use 51 or 90-51 since it is the angle is meant to be between the normal and the object not the object and the surface right?

A metallic sphere of radius 22 cm is negatively charged. The magnitude of the resulting electric field, close to the outside surface of the sphere, is 1.8 × 10^2 N/C. Calculate the net electric flux (in Nm^2/C) outward through a spherical surface surrounding, and just beyond, the metallic sphere's surface.

I'm thinking just E*A*cos(theta) again.. Would the answer be negative because it is negatively charged?

Two concentric spherical shells of radii R1=1 m and R2=2 m, contain charge Q1=0.005 C and Q2=0.0065 C respectively.
Calculate the Electric field at a distance r=1.79 m from the centerpoint of the spheres

I have absolutely no idea on this one.. How does it work with the two charges? And what if I was calculating the field outside the two spheres, would that be any different?

A very long solid nonconducting cylinder of radius 18.3 cm possesses a uniform volume charge density of 1.68 μC/m^3. Determine the magnitude of the electric field (in N/C) inside the cylinder at a radial distance of 8.8 cm from the cylinder's central axis

Heres what I've thought of, multiply the volume charge density by the volume of the cylindar to get the charge in μC, then use E=kQ/r^2 to get the magnitude of the electric field. Is that right? Edit: That won't work because I don't have a length of the cylindar to get the volume... Woops.

Thanks for any help, btw I don't want numbers or any answers I'd rather hear the process then get the numbers myself so I can figure out other problems of similar nature..

Last edited: Aug 21, 2005
2. Aug 21, 2005

mukundpa

oooooooooooo
what is the area of a circle 2*pi*r ???? Check it.

3. Aug 21, 2005

arutha

Oh yeah I forgot the square after the r... I wrote it down on the sheet, just missed typing it.

4. Aug 21, 2005

mukundpa

A = (Pi)*r^2

5. Aug 21, 2005

mukundpa

For the rest problems go through Guass's Theorem

6. Aug 22, 2005

arutha

Well, I got them all except the last one now. Still have absolutely no idea how to do it, I've gone through my text book, lecture notes and everythnig but can't find anything on it.

7. Aug 22, 2005

mukundpa

The distance of the point at which the field magnitude is required is 8.8 cm which is less then the radius of cylinder 18.3 cm.
Consider a coaxial cylindrical Gaussian surface of radius 8.8 cm and apply the Gauss’s theorem. Remember the charge to be taken within the Gaussian surface.