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Electric field in a cavity

  1. Oct 7, 2013 #1
    Hi, I am dealing with a problem in Electrostatics.

    1. The problem statement, all variables and given/known data

    There is a sphere with a spherical cavity in it. The sphere itself does not have net charge, but inside the cavity, there is a point charge at the center of the cavity. What's the electric field inside the cavity?

    2. Relevant equations

    Gauss' Law, E=Q/(4*Pi*epsilon0*r^2)

    3. The attempt at a solution

    I assume the field is 0 because the induced charges on the cavity surface cancels the field of the point charge in it. Is this assumption correct?
     
    Last edited: Oct 7, 2013
  2. jcsd
  3. Oct 7, 2013 #2
    No, the assumption isn't correct. The induced charge in fact support that there is an electric field inside the cavity. try to work it out
     
  4. Oct 7, 2013 #3

    collinsmark

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    That assumption isn't correct for the electric field inside the cavity (inside of the surface containing the induced charges).

    If it helps to understand why, remember what the electric field is inside of a uniformly charged, spherically symmetric shell without any other charges in it. Then consider what the electric field is if there is an additional charge at the center, all else being the same.

    Now use Gauss' Law to apply that to this problem with the cavity. You shouldn't even have to assume that the cavity is symmetric -- it can be of any shape. Also, the cavity, and the charge inside of it, doesn't need to even be centered in the conducting sphere -- it can be anywhere within the sphere.

    After you answer this step, it's the next steps that end up being rather fascinating and insightful. You will be invariably asked next to find the electric field within the conducting sphere, but outside the cavity, and then to find the electric field outside of the entire conducting sphere.

    Hint: At first this might seem like a very mathematically intense exercise, but it is not. If you use Gauss' Law it turns out to be a surprisingly simple problem (well, comparatively simple for an electrostatics problem anyway). Most of this exercise is thinking about Gauss' Law qualitatively.
     
  5. Oct 8, 2013 #4
    You're right, I actually confused this problem with a dielectrical sphere. It is pretty obvious using Gauss' Law that there has to be an electric field inside the cavity when there is a charge inside it (which ends at the surface of the cavity to guarantee that the conductor is field-free). Thank you very much!
     
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