(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

GIVEN:

a=radius of inner electrode = 0.05 cm

b=radius of outer electrode = 0.5 cm

Vo = 130 V

QUESTION: What is the electric field at surface of the inner electrode in units of V/m?

2. Relevant equations

Given equations

Potential at radius r b/w inner&outer electrodes is

V=Vo*ln(r/a) (Eq 1)

Elect field at r is

E(V/m) = (1/r)*[V/ln(b/a)] Eq (2)

3. The attempt at a solution

First in finding the V at surface of inner electrode,

the value of r is same as a because it's at surface, so the ln (r/a) term

becomes zero. So that is where I am stuck. Are the equations I am given correct?

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# Homework Help: Electric Field in Coaxial Cable

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