# Electric field inside a metal ball

A uniform electric field of 1.0 N/C is set up by a uniform distribution of charge in the xy-plane. What is the electric field inside a metal ball placed 0.50 m above the xy-plane?

E= Fe/q
E=(kq1q2)/r^2

0= ((9x10^9)(1)(q2))/.5^2

q2= 0

does this sound right?