- #1

ahuebel

- 11

- 0

It seems pretty basic but I am stuck on a point (assuming I am even on the right track). Because of symmetry I assume Ex = 0 so I just need to find Ey. the y component of dE is k*(dq/r^2) * sin (theta).

So the sum of the little dE's can be found by integrating across the semicircle. The integral would look something like 2k*dq/r^2 *[integral from 0 to pi/2]sin (theta). I know dq=lambda/dL where L is the length of the bent rod. How do I go from dL to d(theta)?

Thanks!